Resonant Circuits
Remember that as frequency increases inductive reactance increases. On
the other hand, as frequency increases capacitive reactance decreases.
This means that, with any LC circuit, there must be a frequency where
the inductive reactance and capacitive reactance are the same. The
frequency where inductive reactance and capacitive reactance are equal
is called the resonant frequency.
The following graph shows the capacitive reactance of a 100 microfarad
capacitor over a range of frequencies from 10Hz to 200Hz. It also shows
the inductive reactance of a 100mH inductor over the same range. Notice
that he curves cross at 50.4Hz. This is the frequency where the
inductive reactance and the capacitive reactance are the same.
At the resonant frequency, the capacitive reactance and inductive reactance are the same. Therefore, the following is true:
At the resonant frequency:
By manipulating this formula according to the rules of the basic algebraic formula we can see that the following is also true:
1 = (
2πƒC) X (2πƒL)
Applying the commutative property of multiplication we can rearrange the formula as follows.
1 = 22π2ƒ2LC
Applying the rules for the basic algebraic formula again we can get:
Finally, taking the square root of the whole formula we can produce the
following formula to find the resonant frequency (
ƒR) of a resonant
circuit.:
In the following circuit the resonant frequency would be calculated by
plugging the values for the inductor and capacitor into the above
formula:
The procedure to solve this formula is:
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Multiply the inductance by the capacitance.
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Take the square root of the product.
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Multiply that by 6.28.
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Take the reciprocal of that product.
To calculate the resonant frequency for the above circuit on a typical scientific calculator type:
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2
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X
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0
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0
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0
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2
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=
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√
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X
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6
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2
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8
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1/χ
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25.2
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This gives a resonant frequency of 25.2 Hz. Therefore, at 25.2 Hz, the
capacitive reactance and the inductive reactance are the same.
If either inductance or capacitance increases, the resonant frequency
decreases. Likewise, if either the inductance or capacitance decreased,
the resonant frequency increases (if anything below the division line
in the formula increases, the answer will decrease and vice versa).
Series Resonance
In the following example the inductor and capacitor are connected in
series. As shown above, to find the total reactance, the capacitive
reactance is subtracted from the inductive reactance. Since the
inductive reactance and the capacitive reactance are equal at the
resonant frequency, the total reactance will be zero at the resonant
frequency.

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A series resonant circuit
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The
impedance of a series resonant circuit with no resistance. Note that
the impedance (the total reactance in this case) is zero at the
resonant frequency.
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At frequencies below the resonant frequency the capacitive reactance
will dominate the circuit and the impedance will be greater than zero.
At frequencies above the resonant frequency the inductive reactance
will dominate the circuit and the impedance will also be greater than
zero.
The following circuit has a 20 ohm resistor in series with the
capacitor and inductor. Since the capacitive reactance and inductive
reactance cancel each other at the resonant frequency, the only thing
left is the resistance. Therefore, at the resonant frequency, the
impedance is equal to the value of the resistor. Resistors aren't
affected by frequency. That is why the resistance is a flat line in the
following graph.

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Series resonant circuit with resistance
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Again, the impedance is higher when the frequency is above or below the resonant frequency.
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In a series resonant circuit, the impedance will always be lowest at
the resonant frequency. If there is any resistance in the circuit, the
value of that resistance will be the impedance at the resonant
frequency.
Parallel Resonance
With a parallel circuit at DC, the total impedance will always be lower than
the lowest impedance (recall resistors in parallel). However, things are
different with a capacitor and inductor in parallel. At DC, the inductor
will be a short circuit discounting any resistance of the inductor wire
(here, we will assume that the resistance of the wire is zero). At DC, the
capacitor will act as an open circuit, discounting any leakage current. The
net circuit is a short circuit in parallel with an open circuit. Therefore,
at DC, the circuit will have nearly zero impedance. At very high
frequencies, the capacitor acts as a short circuit, and the inductor acts as
an open circuit. Again we have a short circuit in parallel with an open
circuit. Therefore, at very high frequencies, the circuit has nearly zero
impedance.
Things are different between these extremes. The inductor
and capacitor each store energy during one part of each cycle and release it
at the opposite part. The components are also working 180 degrees out of
phase, meaning that when the capacitor releases current in one direction,
the inductor releases current in the opposite direction. At low frequencies,
the inductor dominates, and at high frequencies, the capacitor dominates.
Either way, a considerable current flows through the circuit. However, at
the resonant frequency, the components attempt to release equal amounts of
current in opposite directions. The net result is no current flow.
Therefore, at the resonant frequency, the impedance of the circuit
approaches infinity.

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A Parallel Resonant Circuit
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Impedance of a parallel resonant circuit
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Another way to look at it is that current flowing one way out of the
inductor is sucked up by the capacitor trying to send current in the
opposite direction. The net result is no current in that direction.
Likewise, current flowing the other way out of the capacitor is sucked up by
the inductor trying to send current opposite to the capacitor. Again, there
is no net current flow. The external signal feeding the circuit peaks just
as the voltage across the circuit peaks with an equal voltage with opposite
polarity (180 degrees out of phase). Thus, the circuit appears to be an
infinite impedance. If there were no resistance in the inductor, dissipating
energy as heat, there would be no current flow through the circuit at the
resonant frequency. (I have heard that there are experimental
superconducting parallel resonant circuits submerged in liquid nitrogen that
have been "ringing" for decades without loss of energy.)
If you add a resistor to a parallel resonant circuit, that resistor
will impose a limit on the total impedance of the circuit. At the
resonant frequency the capacitive reactance and the inductive reactance
combine in such a way that the impedance approaches infinity. Putting a resistor
in parallel with that nearly infinite impedance results in a total impedance
essentially equal to the value of the resistor.
Over all, the impedance of a parallel resonant circuit is highest at
the resonant frequency. If there is any resistance in the circuit, the
impedance at the resonant frequency will be the value of that resistor.

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Parallel resonant circuit with resistance. R = 20 ohms.
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Parallel resonant circuit impedance with 20 ohms of resistance.
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Parallel resonant circuit with resistance. R = 90 ohms.
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Parallel resonant circuit impedance with 90 ohms of resistance.
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Q factor
Notice that with the higher resistance the impedance peaks more
sharply. The steepness of the sides of this curve and the narrowness of
the area is referred to as "Q" (from the word "quality"). The steeper
the sides and the narrower the area, the higher the Q.
In a parallel resonant circuit, the more resistance you have, the
higher the Q. In a series resonant circuit, the more resistance you
have, the lower the Q. In a parallel resonant circuit with no resistor,
the only resistance in the circuit is the inherent resistance of the
inductor. This resistance acts in series with the inductor. Therefore,
in either a series or parallel resonant circuit, the more resistance
inherent in the inductor, the lower the Q. To have resonant circuits
with a high Q you need inductors with low resistance.